What would be the solution to K(x)=e^2x-3 ,x=2? Can anyone explain how you solve it?

Tuesday, July 15, 2008

$\displaystyle{K}{\left({x}\right)}={{e}}^{{{2}{x}}}-{3}$

To evaluate this function when x=2, plug-in this value.

$\displaystyle{K}{\left({2}\right)}={{e}}^{{{2}\cdot{2}}}-{3}$

$\displaystyle{K}{\left({2}\right)}={{e}}^{{4}}-{3}$

This is the exact value of the function K(x) when x=2.

Using a calculator to compute, it yields an approximate value

$\displaystyle{K}{\left({2}\right)}\approx{51.6}$

Therefore, the exact value of the function K(x) when x=2 is $\displaystyle{{e}}^{{4}}-{3}$ .

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