What would be the solution to K(x)=e^2x-3 ,x=2? Can anyone explain how you solve it?

`K(x)=e^(2x) - 3`

To evaluate this function when x=2, plug-in this value.

`K(2) = e^(2*2) - 3`

`K(2) = e^4-3`

This is the exact value of the function K(x) when x=2.

Using a calculator to compute, it yields an approximate value

`K(2) ~~ 51.6`

Therefore, the exact value of the function K(x) when x=2 is  `e^4-3` .