You may subtract the third equation from the first, such that:
`y - 2z = 0 => y = 2z`
Replace 2z for y in equations 2 and 3, such that:
`5x + 8z + 22z = 0 => 5x+30z = 0 => x + 6z = 0 => x = -6z`
`4x + 4z + 19z = 0 => 4x + 23z = 0`
`4x + 23z - 4x - 24z = 0 => -z = 0 => z = 0 => x = 0 => y = 0`
Hence, evaluating the solution to the homogeneous system, yields x = y = z = 0.
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