We know that `sin(u+v)=sin(u)cos(v)+cos(u)sin(v).`
`sin(u)` and `cos(v)` are given, let's find `cos(u)` and `sin(v).`
`cos(u)=+-sqrt(1-sin^2(u))=+-sqrt(1-25/169)=+-sqrt(144/169)=+-12/13.`
Select "-" because `u` is in quadrant II.
And `sin(v)=+-sqrt(1-cos^2(v))=+-sqrt(1-9/25)=+-4/5.`
Select "+" because `v` is in quadrant II.
Finally `sin(u+v)=(5/13)*(-3/5)+(-12/13)*(4/5)=-1/65*(15+48)=-63/65.`
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