Monday, December 5, 2011

A 15,250 kg jet plane is pushed with a thrust of 2,347,000 newtons. What is the acceleration of the jet?

According to Newton's Second Law of Motion, the force can be calculated as a product of mass and acceleration. That is,


F = m x a


where, m is the mass of the object and a is its acceleration. In this case,


F = 2,347,000 N and m = 15,250 kg


The acceleration (a) of the jet plane can be calculated as:


a = F/m = (2,347,000)/(15,250) = 153.9 m/s^2


Thus, the acceleration of the jet plane is 153.9 m/s^2. 


This means that the jet plane would be propelled with an acceleration of 153.9 m/s^2. In comparison, our fast cars go from 0 to 60 km per hour in say 4 seconds or so and have an acceleration of 4.2 m/s^2. One can imagine how fast the jet plane accelerates, in comparison.


Hope this helps. 

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