`x + 2z = 5, 3x - y - z = 1, 6x - y + 5z = 16` Solve the system of linear equations and check any solutions algebraically.

You may replace `5 - 2z` for x in the second and third equations, such that:

`3(5-2z) - y - z = 1 => -y - 7z = -14`

`6(5-2z) - y + 5z = 16 => -y - 7z = -14`

You should notice that you have obtained two equivalent equations, hence, the lines represented by these equations are coincident.

Hence, evaluating the solutions to the system yields that there is an infinite number of solutions.