Saturday, March 15, 2014

The temperature of a brass cylinder of mass 100g was raised to 100 degree Celsius and transferred to a thin aluminum can of negligible heat...

The amount of heat lost by brass cylinder is transferred to paraffin. The amount of heat loss by the brass cylinder is given as


= mass x heat capacity x change in temperature


= 100 x 380 x (100 - 20) joules


The amount of heat gained by paraffin is given as


= mass x heat capacity x change in temperature


= 150 x heat capacity x (20 - 11)


Since amount of heat is constant, 


100 x 380 x (100 - 20) = 150 x heat capacity x (20 - 11)


Solving this, we get the heat capacity of paraffin as 2251.8 J/kg/K. 


In this solution, heat loss to aluminum is neglected since heat capacity of the aluminum can is negligible. Any other heat loss has also been neglected.


Hope this helps.

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