How many grams of water are produced from 52 g of C3H8? C3H8 + 5O2 → 3CO2 + 4H2O

The balanced chemical reaction is given as:

`C_3H_8 + 5O_2 -> 3CO_2 + 4H_2O`

This is the oxidation reaction of propane (C3H8). On reaction with oxygen, propane produces carbon dioxide and water. 

The molar mass of propane = 3 x atomic mass of carbon  + 8 x atomic mass of hydrogen = 3 x 12 + 8 x 1 = 44 g/mole

Similarly, the molar mass of water = 2 x atomic mass of hydrogen + 1 x atomic mass of oxygen = 2 x 1 + 1 x 16 = 18 g/mole

Using stoichiometry, 1 mole of propane reacts with 5 moles of oxygen and produces 3 moles of carbon dioxide and 4 moles of water.

Here we are given with 52 g of propane. 

since 1 mole propane produces 4 moles water

or, 44 gm propane produces 4 x 18 = 72 g water

or, 52 gm propane produces 72/44 x 52 g of water

= 85.1 g of water. 

Thus, 52 gm of propane will produce 85.1 g of water.

Hope this helps.