The shell has the radius x, the cricumference is `2pi*x` and the height is `e^(-x^2)` , hence, the volume can be evaluated, using the method of cylindrical shells, such that:
`V = 2pi*int_0^1 x*e^(-x^2) dx`
You need to use substitution method to solve the integral, such that:
`-x^2 = u => -2xdx = du => xdx = -(du)/2`
`V = 2pi*int_(u_1)^(u^2) e^u*(-du)/2`
`V = -pi*e^u|_(u_1)^(u^2)`
`V = -pi*e^(-x^2)|_0^1`
`V = -pi*(e^(-1^2) - e^(-0^2))`
`V = -pi*(1/e - e) => V = pi*(e - 1/e)`
`V = ((e^2-1)*pi)/e`
Hence, evaluating the volume, using the method of cylindrical shells, yields `V = ((e^2-1)*pi)/e.`
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