Let the `phi` operation be defined for all x and y by the equation `x phi y = (2y)/(3x)` Then `4 phi (2 phi 3) = ?`

Saturday, October 27, 2012

Let the $\displaystyle\phi$ operation be defined for all x and y by the equation $\displaystyle{x}\phi{y}=\frac{{{2}{y}}}{{{3}{x}}}$ Then $\displaystyle{4}\phi{\left({2}\phi{3}\right)}=?$

Hello!

The first operation to be performed is that in parentheses, i.e. $\displaystyle{2}\phi{3}.$ By the conditions,

$\displaystyle{2}\phi{3}$ = (2*second operand)/(3*first operand) = (2*3)/(3*2) = 1.

Now, perform $\displaystyle{4}\phi{1}:$

$\displaystyle{4}\phi{1}$ = (2*second operand)/(3*first operand) =(2*1)/(3*4)=1/6.

This is the answer. Note that $\displaystyle{\left({4}\phi{2}\right)}\phi{3}={\left(\frac{{4}}{{12}}\right)}\phi{3}={\left(\frac{{1}}{{3}}\right)}\phi{3}=\frac{{6}}{{1}}={6},$ i.e. this operation isn't associative.

Blog

Saturday, October 27, 2012

Let the $\displaystyle\phi$ operation be defined for all x and y by the equation $\displaystyle{x}\phi{y}=\frac{{{2}{y}}}{{{3}{x}}}$ Then $\displaystyle{4}\phi{\left({2}\phi{3}\right)}=?$

No comments:

Post a Comment

What was the device called which Faber had given Montag in order to communicate with him?

Saturday, October 27, 2012

Let the operation be defined for all x and y by the equation Then

No comments:

Post a Comment

What was the device called which Faber had given Montag in order to communicate with him?

Let the $\displaystyle\phi$ operation be defined for all x and y by the equation $\displaystyle{x}\phi{y}=\frac{{{2}{y}}}{{{3}{x}}}$ Then $\displaystyle{4}\phi{\left({2}\phi{3}\right)}=?$